Question6.1:I had definition char a[6] in one source file,and in another I declared extern char *a

那个谁

Q: I had the definition char a[6] in one source file, and in another I declared extern char *a. Why didn't it work?
A: In one source file you defined an array of characters and in the other you declared a pointer to characters. The declaration extern char *a does not declare an array and therefore does not match the actual definition. The type pointer-to-type-T is not the same as array-of-type-T. Use extern char a[].

那个谁

问题：我在一个源文件中定义了一个char [6]，在另一个文件中声明了extern char *a。为什么不行？
回答：你在一个文件中定义了一个字符数组，而在另一个文件中你声明了一个字符指针。对于声明extern char *不是声明的数组，因此不能和真正的定义相匹配。类型T的指针和类型T的数组并不是一样的类型。请使用extern char a[]。